Mass Balance

5.2ENERGY BALANCE 5.2.1Introduction Energy equilibrize in the crossroadion of fructosyltransferase the finale of heat macrocosm released and absorbed during the reactions. The heat substance equivalence at every constant pressure is; (J/mol.K) From that we groundwork figure the heat heart change that is given by, ?? = then the molar point ramble is given by, Ni= No= Flowrateconcentrationmolecular weight The general balance compare of the energy at calm down state is Q = ?H + W where Q = heat absorbed or released ?H = enthalpy change W = work done 5.2.2Seed Fermenter ground on the chemic properties handbook, the Cp of water, ammonium hydroxide and carbon dioxide are as survey: Table 3.2 come alive capacity, Cp for water, ammonia, and carbon dioxide Component|  | Cp= A+ BT + CT2 + DT3 + ET4 [T(K)]|  |  | A| B| C| D| E| water supply| 92.053| -3.9953x10-2| -2.1103x10-4| 5.3467x10-7| -| ammonia| -182.157| 3.3618| 1.4398x10-2| 2.0371x10-5| -| Carbon dioxide| 27.437| 4.2315x10-2| -1.9555x10-5| 3.9968x10-9|  -2.

9872x10-13| Since the protect of Cp for biomass, sucrose and fructosyltransferase is not getable from the chemical properties handbook, therefore it should be calculated as keep company: From special Kopps rule, The item heat capacity for for each one touch are: C = 10.98 J/mol.K H = 7.56 J/mol.K O = 13.42 J/mol.K N = 18.74 J/mol.K Cp for sucrose is Cp = 1(10.98) + 1.83(7.56) + 0.916 (13.42) = 37.1075 J/mol.K Cp for product is Cp= 1(10.98) + 2.09(7.56) + 0.53(13.42) + 0.275(18.74) = 39.0465 J/mol.K Cp for biomass is Cp = 1(10.98) + 1.46(7.56) + 0.385(13.42) + 0.23(18.74) = 31.4945 J/mol.K To calculate heat capacity, ?H = T1T2Cp dTIf you indispensableness to get a full essay, order it on our website: Ordercustompaper.com

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